Q.The equation of the hyperbola with centre (0,0) and transverse axis along x-axis with length 6 and conjugate axis length 8 is

\dfrac{x^2}{9} - \dfrac{y^2}{16} = 1

\dfrac{x^2}{16} - \dfrac{y^2}{9} = 1

\dfrac{y^2}{9} - \dfrac{x^2}{16} = 1

\dfrac{y^2}{16} - \dfrac{x^2}{9} = 1

The correct solution involves applying the fundamental concept to derive the final value step by step...

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