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JEE Main 2007Medium

Q.The equation of the tangent to the ellipse x2/9+y2/4=1x^2/9 + y^2/4 = 1 at the point (3 cos θ, 2 sin θ) is

a
xcos⁡θ9+ysin⁡θ4=1\dfrac{x \cos \theta}{9} + \dfrac{y \sin \theta}{4} = 1
b
xcos⁡θ3+ysin⁡θ2=1\dfrac{x \cos \theta}{3} + \dfrac{y \sin \theta}{2} = 1
c
xsin⁡θ3+ycos⁡θ2=1\dfrac{x \sin \theta}{3} + \dfrac{y \cos \theta}{2} = 1
d
xsin⁡θ9+ycos⁡θ4=1\dfrac{x \sin \theta}{9} + \dfrac{y \cos \theta}{4} = 1

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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