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JEE Main 2003Medium

Q.The equation of the ellipse with centre at (1,1) and passing through (1,4) and (4,1) is

a
(x−1)29+(y−1)29=1\dfrac{(x-1)^2}{9} + \dfrac{(y-1)^2}{9} = 1
b
(x−1)29+(y−1)24=1\dfrac{(x-1)^2}{9} + \dfrac{(y-1)^2}{4} = 1
c
(x−1)24+(y−1)29=1\dfrac{(x-1)^2}{4} + \dfrac{(y-1)^2}{9} = 1
d
(x−1)216+(y−1)216=1\dfrac{(x-1)^2}{16} + \dfrac{(y-1)^2}{16} = 1

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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