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JEE Main 2018Medium

Q.The equation of the tangent to the hyperbola x2/9y2/4=1x^2/9 - y^2/4 = 1 parallel to the line y = x + 1 is

a
y=x±13y = x \pm \sqrt{13}
b
y=x±5y = x \pm \sqrt{5}
c
y=x±3y = x \pm 3
d
y=x±2y = x \pm 2

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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