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JEE Main 2005Medium

Q.The equation of the ellipse with focus (0,3) and directrix y = -3 is

a
x29+y236=1\dfrac{x^2}{9} + \dfrac{y^2}{36} = 1
b
x236+y29=1\dfrac{x^2}{36} + \dfrac{y^2}{9} = 1
c
x227+y236=1\dfrac{x^2}{27} + \dfrac{y^2}{36} = 1
d
x236+y227=1\dfrac{x^2}{36} + \dfrac{y^2}{27} = 1

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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