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Q.If a⃗×b⃗=c⃗\vec{a} \times \vec{b} = \vec{c} and b⃗×c⃗=a⃗\vec{b} \times \vec{c} = \vec{a}, then

a
∣a⃗∣=∣c⃗∣|\vec{a}| = |\vec{c}|
b
a⃗∥c⃗\vec{a} \parallel \vec{c}
c
a⃗=c⃗\vec{a} = \vec{c}
d
∣b⃗∣2=∣a⃗∣∣c⃗∣|\vec{b}|^2 = |\vec{a}| |\vec{c}|

Correct Answer: Option D

The correct solution involves applying the fundamental concept to derive the final value step by step...

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