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Q.If ∣a⃗+b⃗∣2=∣a⃗∣2+∣b⃗∣2|\vec{a} + \vec{b}|^2 = |\vec{a}|^2 + |\vec{b}|^2, then

a
a⃗⋅b⃗=0\vec{a} \cdot \vec{b} = 0
b
a⃗=b⃗\vec{a} = \vec{b}
c
∣a⃗∣=∣b⃗∣|\vec{a}| = |\vec{b}|
d
a⃗=−b⃗\vec{a} = -\vec{b}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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