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Q.The electrostatic potential energy of two point charges qq each placed at opposite corners of a square of side aa and zero at the other two corners is

a
q24πϵ0a(2+2)\dfrac{q^2}{4\pi\epsilon_0 a} (2 + \sqrt{2})
b
q24πϵ0a(1+2)\dfrac{q^2}{4\pi\epsilon_0 a} (1 + \sqrt{2})
c
q224πϵ0a\dfrac{q^2 \sqrt{2}}{4\pi\epsilon_0 a}
d
2q24πϵ0a\dfrac{2q^2}{4\pi\epsilon_0 a}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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