Home/Question #3993
JEE Main 2006Medium

Q.The unit vector parallel to the resultant of the vectors a=4i^+3j^+6k^\vec{a} = 4\hat{i} + 3\hat{j} + 6\hat{k} and b=i^+3j^8k^\vec{b} = -\hat{i} + 3\hat{j} - 8\hat{k} is

a
3i^+6j^2k^7\dfrac{3\hat{i} + 6\hat{j} - 2\hat{k}}{7}
b
3i^+6j^2k^49\dfrac{3\hat{i} + 6\hat{j} - 2\hat{k}}{\sqrt{49}}
c
3i^+6j^+2k^7\dfrac{3\hat{i} + 6\hat{j} + 2\hat{k}}{7}
d
3i^6j^+2k^7\dfrac{-3\hat{i} - 6\hat{j} + 2\hat{k}}{7}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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