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Q.If a⃗×b⃗=b⃗×c⃗\vec{a} \times \vec{b} = \vec{b} \times \vec{c} and b⃗≠0⃗\vec{b} \neq \vec{0}, then

a
a⃗=c⃗+kb⃗\vec{a} = \vec{c} + k \vec{b}
b
a⃗−c⃗\vec{a} - \vec{c} parallel to b⃗\vec{b}
c
a⃗=c⃗\vec{a} = \vec{c}
d
a⃗⋅b⃗=0\vec{a} \cdot \vec{b} = 0

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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