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Q.The position vector of the point dividing AB externally in ratio 3:1 where A has position vector a⃗\vec{a}, B has b⃗\vec{b} is

a
3b⃗−a⃗2\dfrac{3\vec{b} - \vec{a}}{2}
b
3a⃗−b⃗2\dfrac{3\vec{a} - \vec{b}}{2}
c
a⃗−3b⃗2\dfrac{\vec{a} - 3\vec{b}}{2}
d
3a⃗+b⃗4\dfrac{3\vec{a} + \vec{b}}{4}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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