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JEE Main 2024Medium

Q.The plane passing through the point (4,-1,2) and perpendicular to the line x−21=y−3−2=z+13\dfrac{x-2}{1} = \dfrac{y-3}{-2} = \dfrac{z+1}{3} has equation

a
x−2y+3z−12=0x - 2y + 3z - 12 = 0
b
x+2y−3z+12=0x + 2y - 3z + 12 = 0
c
x−2y+3z+12=0x - 2y + 3z + 12 = 0
d
x+2y+3z−12=0x + 2y + 3z - 12 = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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