Q.The foot of the perpendicular drawn from the point (0,4,2) to the line $\dfrac{x+5}{3} = \dfrac{y-3}{4} = \dfrac{z+2}{5}$ is

(1,2,3)

(-1,2,3)

(1,-2,3)

(-1,-2,3)

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.The foot of the perpendicular drawn from the point (0,4,2) to the line x+53=y−34=z+25\dfrac{x+5}{3} = \dfrac{y-3}{4} = \dfrac{z+2}{5}3x+5​=4y−3​=5z+2​ is