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JEE Main 2013Medium

Q.The distance between the planes x+2y+3z+4=0x + 2y + 3z + 4 = 0 and 2x+4y+6z+8=02x + 4y + 6z + 8 = 0 is

a
4/144/\sqrt{14}
b
2/142/\sqrt{14}
c
4/74/7
d
8/148/\sqrt{14}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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