Q.The equation of the line passing through (1,2,3) and parallel to the planes x - y + 2z = 5 and 3x + y + z = 6 is

\vec{r} = (\hat{i} + 2\hat{j} + 3\hat{k}) + \lambda (-\hat{i} + \hat{j} + \hat{k})

\vec{r} = (\hat{i} + 2\hat{j} + 3\hat{k}) + \lambda (\hat{i} - \hat{j} + \hat{k})

\vec{r} = (\hat{i} + 2\hat{j} + 3\hat{k}) + \lambda (\hat{i} + \hat{j} - \hat{k})

\vec{r} = (\hat{i} + 2\hat{j} + 3\hat{k}) + \lambda (-\hat{i} - \hat{j} + \hat{k})

The correct solution involves applying the fundamental concept to derive the final value step by step...

Already a member? Login here