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JEE Main 2008Medium

Q.The distance from the point (1,0,2) to the plane x2y+3z=4x - 2y + 3z = 4 is

a
1/141/\sqrt{14}
b
5/145/\sqrt{14}
c
3/143/\sqrt{14}
d
7/147/\sqrt{14}

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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The distance from the point (1,0,2) to the plane x - 2y + 3... | ParikshaNiti