Q.The lines $\dfrac{x-1}{2} = \dfrac{y-2}{3} = \dfrac{z-3}{4}$ and $\dfrac{x-4}{5} = \dfrac{y-1}{2} = z$ intersect at the point

(1,2,3)

(4,1,0)

(7,5,7)

no intersection

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.The lines x−12=y−23=z−34\dfrac{x-1}{2} = \dfrac{y-2}{3} = \dfrac{z-3}{4}2x−1​=3y−2​=4z−3​ and x−45=y−12=z\dfrac{x-4}{5} = \dfrac{y-1}{2} = z5x−4​=2y−1​=z intersect at the point