Q.The shortest distance between the lines $\dfrac{x-1}{2} = \dfrac{y+1}{-3} = \dfrac{z}{1}$ and $\dfrac{x+1}{1} = \dfrac{y-1}{2} = \dfrac{z-2}{3}$ is

\sqrt{29}/4

\sqrt{29}/2

29/4

29/2

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.The shortest distance between the lines x−12=y+1−3=z1\dfrac{x-1}{2} = \dfrac{y+1}{-3} = \dfrac{z}{1}2x−1​=−3y+1​=1z​ and x+11=y−12=z−23\dfrac{x+1}{1} = \dfrac{y-1}{2} = \dfrac{z-2}{3}1x+1​=2y−1​=3z−2​ is