Q.The equation of the plane which is parallel to the lines $\dfrac{x-1}{1} = \dfrac{y-2}{2} = \dfrac{z-3}{3}$ and $\dfrac{x-2}{2} = \dfrac{y-3}{3} = \dfrac{z-4}{4}$ and passes through (1,2,3) is

x + y + z = 6

x - y + z = 0

2x + 3y + 4z = 17

x + y - z = 0

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.The equation of the plane which is parallel to the lines x−11=y−22=z−33\dfrac{x-1}{1} = \dfrac{y-2}{2} = \dfrac{z-3}{3}1x−1​=2y−2​=3z−3​ and x−22=y−33=z−44\dfrac{x-2}{2} = \dfrac{y-3}{3} = \dfrac{z-4}{4}2x−2​=3y−3​=4z−4​ and passes through (1,2,3) is