Home/Question #4067
JEE Main 2010Medium

Q.The shortest distance between the line xy=1x - y = 1 and the curve x=y2x = y^2 is

a
1/21/\sqrt{2}
b
2\sqrt{2}
c
11
d
00

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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