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JEE Main 2003Medium

Q.The equation of the plane perpendicular to the line x−11=y+2−2=z−33\dfrac{x-1}{1} = \dfrac{y+2}{-2} = \dfrac{z-3}{3} and passing through (1,-2,-3) is

a
x−2y+3z+10=0x - 2y + 3z + 10 = 0
b
x+2y−3z−10=0x + 2y - 3z - 10 = 0
c
x−2y+3z−10=0x - 2y + 3z - 10 = 0
d
x+2y+3z+10=0x + 2y + 3z + 10 = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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