Q.The shortest distance between the lines $\dfrac{x-2}{1} = \dfrac{y+1}{-2} = \dfrac{z-1}{3}$ and $\dfrac{x-1}{2} = \dfrac{y-2}{3} = \dfrac{z-3}{4}$ is

17/\sqrt{29}

17/29

\sqrt{17}/29

\sqrt{29}/17

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.The shortest distance between the lines x−21=y+1−2=z−13\dfrac{x-2}{1} = \dfrac{y+1}{-2} = \dfrac{z-1}{3}1x−2​=−2y+1​=3z−1​ and x−12=y−23=z−34\dfrac{x-1}{2} = \dfrac{y-2}{3} = \dfrac{z-3}{4}2x−1​=3y−2​=4z−3​ is