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JEE Main 2019Medium

Q.The equation of the plane passing through the points (0, -1, 0), (2,1,0) and parallel to the line x12=y+13=z4\dfrac{x-1}{2} = \dfrac{y+1}{-3} = \dfrac{z}{4} is

a
3x+y2z=13x + y - 2z = 1
b
3xy+2z=13x - y + 2z = 1
c
x+3y2z=5x + 3y - 2z = 5
d
x3y+2z=5x - 3y + 2z = 5

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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