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JEE Main 2015Medium

Q.The distance of the point (2,3,4) from the plane xy+z=5x - y + z = 5 measured parallel to the line x2=y3=z6\dfrac{x}{2} = \dfrac{y}{3} = \dfrac{z}{-6} is

a
7\sqrt{7}
b
272\sqrt{7}
c
373\sqrt{7}
d
474\sqrt{7}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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