Home/Question #4122
JEE Main 2007Medium

Q.The number of solutions of the equation 2sin2xcos2x=12\sin^2 x - \cos 2x = 1 in [0,2π][0, 2\pi] is

a
2
b
4
c
6
d
8

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here