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JEE Main 2005Medium

Q.If tanθ=k\tan \theta = k, then sin2θ\sin 2\theta equals

a
2k/(1+k2)2k/(1+k^2)
b
k/(1+k2)k/(1+k^2)
c
2k/(1k2)2k/(1-k^2)
d
k/(1k2)k/(1-k^2)

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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