Q.If $\sin \theta = 3 \sin(\theta + 2\alpha)$ , then $\tan(\theta + \alpha) \tan \alpha$ equals

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.If sin⁡θ=3sin⁡(θ+2α)\sin \theta = 3 \sin(\theta + 2\alpha)sinθ=3sin(θ+2α), then tan⁡(θ+α)tan⁡α\tan(\theta + \alpha) \tan \alphatan(θ+α)tanα equals