Home/Question #4181

JEE Main 2000Medium

Q.The general solution of $\sin x - 3 \sin 2x + \sin 3x = 0$ is

a

x = n\pi + (-1)^n \pi/6

b

x = n\pi

c

x = 2n\pi + \pi/6

d

x = n\pi/6

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here