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Q.A charged particle of charge qq and mass mm enters a uniform magnetic field BB perpendicularly with speed vv. The time period of revolution is

a
2πmqB\dfrac{2\pi m}{qB}
b
2πqmB\dfrac{2\pi q}{mB}
c
πmqB\dfrac{\pi m}{qB}
d
4πmqB\dfrac{4\pi m}{qB}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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