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Q.A proton and an electron are accelerated through same potential difference. The ratio of their de-Broglie wavelengths is

a
1:11:1
b
mp:me\sqrt{m_p : m_e}
c
me:mp\sqrt{m_e : m_p}
d
mp:mem_p : m_e

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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