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Q.The moment of inertia of a circular ring about an axis passing through its centre and perpendicular to its plane is MR². By perpendicular axes theorem, MI about diameter is

a
MR2/2MR^2/2
b
MR2/4MR^2/4
c
MR2MR^2
d
2MR22MR^2

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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