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JEE Main 2013Medium

Q.The MI of a disc about an axis perpendicular to plane and passing through centre is I. By parallel axes theorem, MI about tangent perpendicular to plane is

a
I+MR2I + MR^2
b
5/4MR25/4 MR^2
c
I+MR2/4I + MR^2/4
d
I+MR2/2I + MR^2/2

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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