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Q.A thin uniform rod of mass M and length L is held vertically with lower end pivoted. It is slightly displaced and released. The angular acceleration when it makes angle θ with vertical is

a
(3gsin⁡θ)/(2L)(3g \sin \theta)/(2L)
b
(3gcos⁡θ)/(2L)(3g \cos \theta)/(2L)
c
(gsin⁡θ)/L(g \sin \theta)/L
d
(2gsin⁡θ)/L(2g \sin \theta)/L

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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