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JEE AdvancedMedium

Q.A force F=kxF=-kx acts on a particle. The potential energy function is

a
kxkx
b
12kx2\frac{1}{2}kx^2
c
12kx2-\frac{1}{2}kx^2
d
kx2kx^2

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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