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Q.A particle moves under force F=kxF=\frac{k}{x}. The work done from x=a to x=b is

a
k(ba)k(b-a)
b
kln(b/a)k\ln(b/a)
c
kln(a/b)k\ln(a/b)
d
k2(b2a2)\frac{k}{2}(b^2-a^2)

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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