Q.A particle of mass m with velocity $\vec{u}=u\hat{i}$ collides elastically with a stationary particle of mass 2m. If the lighter particle scatters at $90^\circ$ , the speed of the heavier particle after collision is

\frac{u}{3}

\frac{2u}{3}

\frac{u}{2}

u

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.A particle of mass m with velocity u⃗=ui^\vec{u}=u\hat{i}u=ui^ collides elastically with a stationary particle of mass 2m. If the lighter particle scatters at 90∘90^\circ90∘, the speed of the heavier particle after collision is