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JEE Main 2010 + NEETMedium

Q.The current in a wire is 5 A. The number of electrons passing per second is

a
3.125 × 101910^{19}
b
5 × 101910^{19}
c
1.6 × 101910^{19}
d
8 × 101810^{18}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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