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JEE Main 2025 + NEETMedium

Q.The force between two charges separated by distance r in a medium of dielectric constant K is

a
14πϵ0Kq1q2r2\dfrac{1}{4\pi \epsilon_0 K} \dfrac{q_1 q_2}{r^2}
b
14πϵ0q1q2Kr2\dfrac{1}{4\pi \epsilon_0} \dfrac{q_1 q_2}{K r^2}
c
14πϵ0q1q2r2\dfrac{1}{4\pi \epsilon_0} \dfrac{q_1 q_2}{r^2}
d
4πϵ0Kq1q2r24\pi \epsilon_0 K \dfrac{q_1 q_2}{r^2}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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