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JEE Main 2025 + NEETMedium

Q.Two point charges +q and -q are placed at distance 2a apart. The electric field at the midpoint is

a
zero
b
14πϵ02qa2\dfrac{1}{4\pi \epsilon_0} \dfrac{2q}{a^2} towards +q
c
14πϵ0qa2\dfrac{1}{4\pi \epsilon_0} \dfrac{q}{a^2} towards +q
d
14πϵ04qa2\dfrac{1}{4\pi \epsilon_0} \dfrac{4q}{a^2} towards +q

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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