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JEE Main 2024 + NEETMedium

Q.A dielectric slab of thickness t is inserted in a parallel plate capacitor of plate separation d (t < d). The capacitance becomes

a
ϵ0A/(dt+t/K)\epsilon_0 A / (d - t + t/K)
b
ϵ0A/(d+t/K)\epsilon_0 A / (d + t/K)
c
ϵ0AK/d\epsilon_0 A K / d
d
ϵ0A/d\epsilon_0 A / d

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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