Q.A thin ring of radius R has charge Q uniformly distributed. The electric field at a point on the axis at distance x from centre is

\dfrac{1}{4\pi \epsilon_0} \dfrac{Q x}{(R^2 + x^2)^{3/2}}

\dfrac{1}{4\pi \epsilon_0} \dfrac{Q}{(R^2 + x^2)}

\dfrac{1}{4\pi \epsilon_0} \dfrac{Q R}{(R^2 + x^2)^{3/2}}

\dfrac{1}{4\pi \epsilon_0} \dfrac{Q x}{(R^2 + x^2)}

The correct solution involves applying the fundamental concept to derive the final value step by step...

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