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JEE Main 2024Medium

Q.A semicircular ring of radius R has uniform charge density λ. The electric field at the centre is

a
λπϵ0R\dfrac{\lambda}{ \pi \epsilon_0 R}
b
2λπϵ0R\dfrac{2\lambda}{ \pi \epsilon_0 R}
c
λ2πϵ0R\dfrac{\lambda}{2 \pi \epsilon_0 R}
d
λϵ0R\dfrac{\lambda}{ \epsilon_0 R}

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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