Q.A rod of length L has charge density λ = λ₀ x/L. The electric field at a point on the axis at distance a from one end is

\dfrac{\lambda_0}{4\pi \epsilon_0} \left( \dfrac{1}{a} - \dfrac{1}{a+L} \right)

\dfrac{\lambda_0 L}{4\pi \epsilon_0 a (a+L)}

\dfrac{\lambda_0}{4\pi \epsilon_0 a}

\dfrac{\lambda_0 L}{2\pi \epsilon_0 a}

The correct solution involves applying the fundamental concept to derive the final value step by step...

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