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Q.A disc of radius R has surface charge density σ = k r (r from centre). The electric field at the centre is

a
zero
b
kR2/(4ϵ0)k R^2 / (4 \epsilon_0)
c
kR/(2ϵ0)k R / (2 \epsilon_0)
d
kR2/(2ϵ0)k R^2 / (2 \epsilon_0)

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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