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Q.A non-conducting ring has charge density λ = λ₀ sinθ. The electric field at centre is

a
λ0πϵ0R\dfrac{\lambda_0}{ \pi \epsilon_0 R}
b
zero
c
λ02πϵ0R\dfrac{\lambda_0}{2 \pi \epsilon_0 R}
d
λ04πϵ0R\dfrac{\lambda_0}{4 \pi \epsilon_0 R}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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