Q.An arc of radius R subtends angle 90° at centre with uniform λ. E at centre is

\dfrac{\sqrt{2} \lambda}{4 \pi \epsilon_0 R}

\dfrac{\lambda}{ \pi \epsilon_0 R}

\dfrac{\lambda}{2 \pi \epsilon_0 R}

\dfrac{\lambda}{4 \pi \epsilon_0 R}

The correct solution involves applying the fundamental concept to derive the final value step by step...

Already a member? Login here