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Q.A rod of length L has λ = k (L - x). The electric field at end x=0 is

a
kL4πϵ0\dfrac{k L}{4\pi \epsilon_0}
b
kL2πϵ0\dfrac{k L}{2\pi \epsilon_0}
c
kL24πϵ0\dfrac{k L^2}{4\pi \epsilon_0}
d
k4πϵ0\dfrac{k}{4\pi \epsilon_0}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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