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JEE Main 2025Medium

Q.A ring of radius R has charge density λ = λ₀ cosθ. The electric field at the centre of the ring is

a
λ0πϵ0R\dfrac{\lambda_0}{ \pi \epsilon_0 R}
b
2λ0πϵ0R\dfrac{2 \lambda_0}{ \pi \epsilon_0 R}
c
zero
d
λ02πϵ0R\dfrac{\lambda_0}{2 \pi \epsilon_0 R}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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