Q.An arc of radius R subtending angle 60° at centre has uniform λ. The electric field at centre is

\dfrac{\lambda}{ \pi \epsilon_0 R}

\dfrac{\lambda}{3 \pi \epsilon_0 R}

\dfrac{\sqrt{3} \lambda}{2 \pi \epsilon_0 R}

\dfrac{\lambda}{6 \pi \epsilon_0 R}

The correct solution involves applying the fundamental concept to derive the final value step by step...

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