Q.A quarter ring has uniform λ. The potential at centre is

\dfrac{\lambda}{2 \pi \epsilon_0 R}

\dfrac{\lambda}{ \pi \epsilon_0 R}

\dfrac{\lambda \sqrt{2}}{2 \pi \epsilon_0 R}

\dfrac{\lambda}{4 \pi \epsilon_0 R}

The correct solution involves applying the fundamental concept to derive the final value step by step...

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